What you'll learn
In this lesson you will learn to:
- square any rational number — whole numbers, negatives, fractions and decimals;
- find square roots of perfect squares, fractions and decimals;
- estimate a square root that is not a whole number (for example, \sqrt{40} is between 6 and 7);
- simplify square roots like \sqrt{72} = 6\sqrt{2};
- solve simple equations like x^2 = 49.
Why it matters on the GED: squares and square roots show up everywhere — in area of squares, in the Pythagorean theorem, in the area of a circle (\pi r^2), in exponent questions and in the no-calculator section ("Which is closest to \sqrt{58}?"). The GED also likes to test the traps: -5^2 versus (-5)^2, and \sqrt{0.36} versus 0.06.
In real life: if you know a square room covers 144 square feet, the square root tells you each wall is 12 feet long — handy for buying baseboard, fencing or flooring.
Words to know
- Square (of a number) — the number times itself: 7^2 = 7 \times 7 = 49.
- Exponent — the small raised number that says how many times to use the base as a factor: in 5^2, the exponent is 2.
- Base — the number being multiplied: in 5^2, the base is 5.
- Perfect square — a number that is the square of an integer: 1, 4, 9, 16, 25, \dots (36 = 6^2).
- Square root — a number that, when squared, gives the original number: a square root of 49 is 7, because 7^2 = 49.
- Radical sign — the symbol \sqrt{\phantom{x}}. The number under it is the radicand: in \sqrt{30}, the radicand is 30.
- Principal (positive) square root — the \sqrt{\phantom{x}} sign always means the non-negative root: \sqrt{49} = 7, not -7.
- Irrational number — a number that cannot be written as a fraction of two integers; its decimal never ends or repeats: \sqrt{2} \approx 1.414\ldots
- Simplified radical — a square root with no perfect-square factor left under the sign: \sqrt{72} = 6\sqrt{2}.
1. Squaring numbers
To square a number, multiply it by itself: n^2 = n \times n.
| n | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 20 | 25 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| n^2 | 1 | 4 | 9 | 16 | 25 | 36 | 49 | 64 | 81 | 100 | 121 | 144 | 169 | 196 | 225 | 400 | 625 |
Memorize the squares from 1^2 to 15^2. They make roots and estimates fast.
The picture shows why it is called "squaring": a square with side 5 is made of 5^2 = 25 unit squares. Area of a square = s^2.
Squaring is not doubling. 6^2 = 36, not 12.
Negatives. A negative times a negative is positive, so the square of any non-zero number is positive: (-6)^2 = (-6)(-6) = 36.
Watch the parentheses! The exponent only applies to what is directly next to it.
- (-6)^2 = 36 (the base is -6)
- -6^2 = -(6^2) = -36 (the base is 6; the minus sign is applied afterwards)
Fractions. Square the top and the bottom: \left(\tfrac{2}{3}\right)^2 = \tfrac{4}{9}.
Decimals. Square the digits, then double the number of decimal places: 0.3^2 = 0.09 (not 0.9), 1.2^2 = 1.44, 0.05^2 = 0.0025.
Zero and one: 0^2 = 0 and 1^2 = 1. A number between 0 and 1 gets smaller when squared: 0.5^2 = 0.25.
2. Square roots
The square root "undoes" squaring. \sqrt{81} asks: what non-negative number times itself is 81? Answer: 9.
- \sqrt{0} = 0, \sqrt{1} = 1, \sqrt{144} = 12, \sqrt{400} = 20.
Fractions: take the root of the top and the bottom.
\sqrt{\frac{49}{64}} = \frac{\sqrt{49}}{\sqrt{64}} = \frac{7}{8}Decimals: the root has half as many decimal places. Write it as a fraction if unsure:
\sqrt{0.36} = \sqrt{\tfrac{36}{100}} = \tfrac{6}{10} = 0.6 \qquad \sqrt{0.0049} = 0.07(Check: 0.6^2 = 0.36 ✓. A common wrong answer is 0.06, but 0.06^2 = 0.0036.)
Negatives under the root. No real number squared is negative, so \sqrt{-49} is not a real number. But -\sqrt{49} = -7 is fine (the minus is outside).
Equations. x^2 = 49 has two solutions: x = 7 and x = -7, because both square to 49. We write x = \pm 7. The symbol \sqrt{49} alone means only +7.
Products and quotients split; sums do not.
- \sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}: \sqrt{4 \cdot 25} = 2 \cdot 5 = 10 ✓
- \sqrt{a + b} \ne \sqrt{a} + \sqrt{b}: \sqrt{16 + 9} = \sqrt{25} = 5, but \sqrt{16} + \sqrt{9} = 7 ✗
3. Estimating and simplifying square roots
Estimating. Most numbers are not perfect squares. To estimate \sqrt{40}:
- Find the perfect squares on either side: 36 < 40 < 49.
- Take roots: 6 < \sqrt{40} < 7.
- 40 is closer to 36 (4 away) than to 49 (9 away), so \sqrt{40} is closer to 6. In fact \sqrt{40} \approx 6.32.
Squares get further apart as numbers grow, so the root is not exactly in proportion — the estimate is a rough guide, and the calculator gives the exact decimal.
Simplifying. Look for the largest perfect-square factor of the radicand and pull its root out front:
\sqrt{72} = \sqrt{36 \cdot 2} = \sqrt{36} \cdot \sqrt{2} = 6\sqrt{2} \sqrt{50} = \sqrt{25 \cdot 2} = 5\sqrt{2} \qquad \sqrt{48} = \sqrt{16 \cdot 3} = 4\sqrt{3}If you use a smaller perfect square (\sqrt{72} = \sqrt{4 \cdot 18} = 2\sqrt{18}), the answer is still equal but not fully simplified; keep going (2\sqrt{18} = 2 \cdot 3\sqrt{2} = 6\sqrt{2}).
Working backwards from area. If a square has area A, its side is s = \sqrt{A}. A square patio of 225\text{ ft}^2 has sides of \sqrt{225} = 15\text{ ft}.
Formulas and rules
a^2 = a \cdot a \qquad \sqrt{a^2} = a \text{ (for } a \ge 0\text{)} \qquad \left(\sqrt{a}\right)^2 = a \sqrt{ab} = \sqrt{a}\,\sqrt{b} \qquad \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \quad (a \ge 0,\ b > 0) x^2 = k \;(k > 0) \;\Rightarrow\; x = \sqrt{k} \text{ or } x = -\sqrt{k}Area of a square: A = s^2, so s = \sqrt{A} (s = side length, A = area).
Formula sheet: the area of a square (A = s^2) is on the GED formula sheet, and so is the Pythagorean theorem, which uses squares and roots. The rules for working with squares and roots above are not on the sheet — memorize them, along with the perfect squares up to 15^2 = 225.
Example 1 (easy): the sign trap
Evaluate (-7)^2 - 3^2.
- (-7)^2 = (-7)(-7) = 49 (the base is -7; negative × negative = positive).
- 3^2 = 3 \times 3 = 9.
- 49 - 9 = 40.
Answer: 40
Check: On the calculator, type ( (−) 7 ) x² − 3 x² → 40 ✓.
Example 2 (word problem): side of a square
A square garden has an area of 144 square feet. How much fencing is needed to go all the way around it?
- Area of a square: A = s^2, so s^2 = 144.
- Side: s = \sqrt{144} = 12 feet (a length cannot be negative, so use only +12).
- Perimeter: 4s = 4 \times 12 = 48 feet.
Answer: 48 feet of fencing
Check: 12 \times 12 = 144 ✓, and four sides of 12 ft make 48 ft ✓.
Example 3: roots of fractions and decimals
Evaluate \sqrt{\tfrac{25}{81}} + \sqrt{0.09}. Give the answer as a fraction.
- \sqrt{\tfrac{25}{81}} = \tfrac{\sqrt{25}}{\sqrt{81}} = \tfrac{5}{9}.
- \sqrt{0.09} = \sqrt{\tfrac{9}{100}} = \tfrac{3}{10} (that is, 0.3).
- Add with LCD 90: \tfrac{5}{9} + \tfrac{3}{10} = \tfrac{50}{90} + \tfrac{27}{90} = \tfrac{77}{90}.
Answer: \tfrac{77}{90}
Check: \tfrac{5}{9} \approx 0.556 and 0.556 + 0.3 = 0.856; 77 \div 90 \approx 0.856 ✓.
Example 4 (GED-hard): estimate without a calculator
Between which two consecutive whole numbers is \sqrt{90}, and which one is it closer to?
- Perfect squares near 90: 9^2 = 81 and 10^2 = 100.
- 81 < 90 < 100, so 9 < \sqrt{90} < 10.
- Distance: 90 - 81 = 9 and 100 - 90 = 10. 90 is slightly closer to 81, so \sqrt{90} is slightly closer to 9.
Answer: between 9 and 10, a little closer to 9 (calculator: \sqrt{90} \approx 9.49).
Check: 9.5^2 = 90.25, which is just above 90, so \sqrt{90} is just under 9.5 ✓.
Example 5 (work backwards, word problem): from cost to size
Tile for a square floor costs $4.50 per square foot. The tile for the whole floor cost $288. How long is each side of the floor?
- Find the area: 288 \div 4.50 = 64 square feet.
- Side of a square: s = \sqrt{64} = 8 feet.
Answer: 8 feet
Check: 8 \times 8 = 64 sq ft, and 64 \times \$4.50 = \$288 ✓.
Using the TI-30XS MultiView
- Square: type the number, then press
x². For a negative, use parentheses and the(−)key:((−)5)x²gives 25. Without parentheses,(−)5x²gives -25 — exactly the -5^2 trap. - Square root: press
2ndthenx²to get \sqrt{\phantom{x}}, type the number, press the right arrow to close the root, thenenter. Example:2ndx²40enter. In MathPrint mode the answer may appear as the simplified root 2\sqrt{10}; presstoggleto see the decimal 6.32455532. - Fractions under a root: press
2ndx², thenn/d, enter 49 and 64, thenenter; the result shows \tfrac{7}{8}. Presstoggleto see 0.875. - Simplified radicals: the calculator may show an answer like 6\sqrt{2} in MathPrint mode; press
toggleto see the decimal 8.485\ldots and compare with the answer choices.
When NOT to use it: questions about perfect squares (\sqrt{144}), estimates ("between which two integers") and sign rules often appear in the no-calculator section. Know your squares to 15^2 so these take seconds.
Common mistakes
- Doubling instead of squaring. Wrong: 6^2 = 12. Right: 6^2 = 6 \times 6 = 36.
- Halving instead of rooting. Wrong: \sqrt{64} = 32. Right: \sqrt{64} = 8 because 8 \times 8 = 64.
- The negative-base trap. Wrong: -5^2 = 25. Right: -5^2 = -25, while (-5)^2 = 25.
- Decimal places. Wrong: \sqrt{0.36} = 0.06 and 0.3^2 = 0.9. Right: \sqrt{0.36} = 0.6 and 0.3^2 = 0.09 (square → double the decimal places; root → half).
- Splitting a sum. Wrong: \sqrt{16 + 9} = 4 + 3 = 7. Right: add first, \sqrt{25} = 5.
- Forgetting the negative solution — or inventing one. x^2 = 49 has two answers, \pm 7; but \sqrt{49} by itself is only 7. And \sqrt{-49} is not a real number (it is not -7).
GED test strategy
- Use the perfect-square "fence". For any root, write the perfect squares just below and above. This eliminates most wrong choices in seconds, without a calculator.
- Square the answer choices. For "what is \sqrt{\ldots}" questions, squaring each choice and comparing is often fastest — and it catches decimal-place errors.
- Check reasonableness. A side length found from an area must be much smaller than the area (for areas bigger than 1). If you got \sqrt{144} = 72, something is off.
- Look for parentheses around negative numbers before squaring. Read -x^2 and (-x)^2 slowly.
- Read what is asked. Area problems may ask for the side, the perimeter or a cost — finding the root is often only step one.
- Units: area is in square units (\text{ft}^2); the root of an area is in plain units (ft).
Check yourself
What is the value of \sqrt{81}?
Hint
Which number, multiplied by itself, gives 81?
Step-by-step solution
- \sqrt{81} asks: what non-negative number times itself equals 81?
- Try perfect squares you know: 8 \times 8 = 64 (too small), 9 \times 9 = 81 ✓.
- The radical sign \sqrt{\phantom{x}} means the principal (non-negative) root, so the answer is 9, not -9.
Answer: 9
Check: 9^2 = 81 ✓.
Tip: Memorize the perfect squares from 1^2 = 1 to 15^2 = 225. Then every square root of a perfect square is instant — and you will not confuse "square root" with "divide by 2".
Check yourself
Evaluate the expression.
(-7)^2 - 3^2Type your answer in the box. Fractions like 3/4 are fine.
Hint
The base of (-7)^2 is -7, including the negative sign. What is a negative times a negative?
Step-by-step solution
- Square the first term. The parentheses mean the base is -7: (-7)^2 = (-7) \times (-7) = 49 (negative × negative = positive).
- Square the second term: 3^2 = 3 \times 3 = 9.
- Subtract: 49 - 9 = 40.
Answer: 40
Check: On the TI-30XS: ( (−) 7 ) x² − 3 x² enter shows 40 ✓.
Tip: Squaring is not doubling. (-7)^2 is not -14 and 3^2 is not 6; if you got -14 - 6 = -20, you doubled. And if you got -49 - 9 = -58, you forgot that the parentheses put the negative sign inside the square.
Recap
- n^2 = n \times n; memorize squares up to 15^2 = 225. Squaring is not doubling.
- \sqrt{\phantom{x}} means the non-negative root: \sqrt{81} = 9. But x^2 = 81 has two solutions, x = \pm 9.
- (-5)^2 = 25 but -5^2 = -25; \sqrt{-25} is not a real number.
- Fractions: root (or square) top and bottom. Decimals: squaring doubles decimal places, rooting halves them.
- Estimate a root between the two nearest perfect squares; simplify by pulling out the largest perfect-square factor.
- \sqrt{ab} = \sqrt{a}\sqrt{b}, but \sqrt{a + b} \ne \sqrt{a} + \sqrt{b}.