Topic Quiz: Physical Science

Question 1 of 10 · Energy: conservation, transformation, flow

The Electromagnetic Spectrum

Light is only one small part of a much larger family of waves called the electromagnetic (EM) spectrum. All EM waves travel at the same speed in empty space, about 3.0 \times 10^8 meters per second. Unlike sound, they do not need a medium (matter) to travel through, so they can cross the vacuum of space. That is how energy from the Sun reaches Earth.

The waves differ in wavelength (the distance from one crest to the next) and frequency (how many waves pass a point each second). The diagram below shows the order of the bands.

The electromagnetic spectrum, not to scale, shown as seven bands from left to right: radio (radio, TV), microwave (ovens, cell phones), infrared (heat lamps, remotes), visible light (human vision), ultraviolet (sunburn, tanning), X-ray (medical images), gamma (nuclear decay). An arrow pointing right shows increasing frequency and energy. An arrow pointing left shows increasing wavelength. Radio radio, TV Microwave ovens, cell phones Infrared heat lamps, remotes Visible human vision Ultraviolet sunburn, tanning X-ray medical images Gamma nuclear decay Increasing frequency and energy Increasing wavelength

For any wave, speed equals frequency times wavelength. Because all EM waves have the same speed, a wave with a higher frequency must have a shorter wavelength. Higher-frequency EM waves also carry more energy, which is why ultraviolet light can damage skin cells while radio waves pass through our bodies harmlessly.

Space between the Sun and Earth is almost a perfect vacuum, yet infrared and visible light from the Sun warm Earth's surface.

Which statement from the passage best explains how this energy reaches Earth?

Answer choices
Hint

Conduction and convection both need particles of matter. What makes EM waves different?

Question 2 of 10 · Work, motion and forces

Pushing Carts in the Lab

A physics class tested how a cart's acceleration depends on the force pulling it. They placed a cart on a smooth, level track and pulled it with a spring scale that measured the net force in newtons (N). A motion sensor measured the cart's acceleration in meters per second squared (m/s²). They tested a 1 kg cart, then added a 1 kg block to make a 2 kg cart and repeated every trial.

Line graph of acceleration in meters per second squared (y-axis, 0 to 5) versus net force in newtons (x-axis, 0 to 4) for two carts. Both lines are straight and start at zero. 1 kg cart: 0 m/s² at 0 N, 1 m/s² at 1 N, 2 m/s² at 2 N, 3 m/s² at 3 N, 4 m/s² at 4 N; 2 kg cart: 0 m/s² at 0 N, 0.5 m/s² at 1 N, 1 m/s² at 2 N, 1.5 m/s² at 3 N, 2 m/s² at 4 N. 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 0 1 2 3 4 Net force (N) Acceleration (m/s²) 1 kg cart 2 kg cart

Newton's second law states that the acceleration of an object equals the net force on it divided by its mass. In the class's notation, F = ma, where F is net force in newtons, m is mass in kilograms and a is acceleration in m/s².

Which conclusion is best supported by the class's results?

Answer choices
Hint

Compare the two lines at the same net force, for example at 2 N.

Question 3 of 10 · Work, motion and forces

Pulling a Sled

A parent pulls a child on a sled across level snow, holding the rope parallel to the ground. Together, the sled and child have a mass of 25 kg. The force diagram shows all the forces acting on the sled.

Force diagram of a sled carrying a child, total mass 25 kg, on level snow. A rope pulls with 150 N to the right. Friction of 40 N acts to the left. Gravity of 245 N acts downward and the normal force of 245 N from the snow acts upward. level snow sled + child 25 kg Rope pull 150 N Friction 40 N Normal force 245 N Gravity 245 N

The net force is the combined effect of all the forces. Forces in opposite directions are subtracted. Newton's first law says an object keeps moving at a constant velocity unless a net force acts on it. Newton's second law says F_{\text{net}} = ma. Newton's third law says that when one object pushes or pulls on a second object, the second object pushes or pulls back on the first with a force of equal size in the opposite direction.

The rope pulls the sled forward with a force of 150 N. According to Newton's third law, as stated in the passage, which force is the reaction to this pull?

Answer choices
Hint

An action-reaction pair acts on two different objects, the same two objects swapped around.

Question 4 of 10 · Work, motion and forces

Drag and drop
Loading a Washing Machine

Two movers need to raise a 600 N washing machine 1.0 m from the street onto the bed of a moving truck. They compare three methods.

MethodDistance the movers' effort movesHeight the machine is raised
Lift it straight up by hand1.0 m1.0 m
Push it up a smooth ramp4.0 m (length of the ramp)1.0 m
Pull rope through a pulley system with 3 supporting ropes3.0 m of rope1.0 m

For a simple machine with no friction, the mechanical advantage (MA) is the effort distance divided by the load distance, and the effort force needed is the load divided by the MA. Work is force times distance, W = Fd. A machine can reduce the force needed, but it cannot reduce the work: without friction, the work put in equals the work done on the load.

Ignore friction. Drag each method into the box that shows how much effort force the movers need, from least force to most force.

Least effort forceMiddleMost effort force

Tap a tile, then tap a box to place it.

Hint

Find the mechanical advantage of each method (effort distance ÷ load distance). A bigger MA means a smaller effort force.

Question 5 of 10 · Chemical properties and reactions

An instant cold pack has a small pouch of water inside a bag of solid ammonium nitrate. When the pack is squeezed, the pouch breaks and the solid dissolves in the water. Within seconds, the pack feels very cold, and an athlete places it on a sprained ankle.

Which statement best describes what happens?

Answer choices
Hint

Cold is not a substance that flows. Ask: is thermal energy moving into the pack or out of it?

Question 6 of 10 · Energy: conservation, transformation, flow

Fill in
Keeping Coffee Hot

A student wanted to know which kind of cup keeps a hot drink warm the longest. She poured 200 g of water at 80 °C into each of three cups: a foam cup, a ceramic mug and a thin steel mug. The cups had the same shape and no lids, and the room stayed at 22 °C. She recorded the water temperature in each cup every 4 minutes for 20 minutes.

Line graph of water temperature in degrees Celsius (y-axis, 0 to 90) versus time in minutes (x-axis, 0 to 20) for 200 g of hot water in three cups. Foam cup: 80 degrees C at 0 min, 76 degrees C at 4 min, 72 degrees C at 8 min, 69 degrees C at 12 min, 66 degrees C at 16 min, 63 degrees C at 20 min; Ceramic mug: 80 degrees C at 0 min, 71 degrees C at 4 min, 64 degrees C at 8 min, 58 degrees C at 12 min, 53 degrees C at 16 min, 49 degrees C at 20 min; Steel mug: 80 degrees C at 0 min, 66 degrees C at 4 min, 56 degrees C at 8 min, 48 degrees C at 12 min, 42 degrees C at 16 min, 38 degrees C at 20 min. 0 10 20 30 40 50 60 70 80 90 0 4 8 12 16 20 Time (minutes) Water temperature (°C) Foam cup Ceramic mug Steel mug 63 °C 49 °C 38 °C

Thermal energy always moves from a warmer object to a cooler one. In this setup, energy moved from the hot water, through the cup walls, into the cooler room air. Materials that let thermal energy pass through easily are called conductors; materials that slow it down are called insulators.

The heat lost by the water in a cup can be found with Q = mc\Delta T, where m is the mass of the water in grams, c = 4.18\text{ J/g}\cdot\text{°C} for water, and \Delta T is the change in temperature.

Using the graph, how many more joules of thermal energy did the water in the steel mug lose than the water in the foam cup during the 20 minutes?

J

Type your answer in the box. Fractions like 3/4 are fine.

Hint

Find each cup's temperature drop from the graph first. The mass and c are the same for both.

Question 7 of 10 · Energy: conservation, transformation, flow

Energy on a Roller Coaster

A roller coaster has no engine after the first hill. A chain lifts the car to the top of hill A, and from then on gravity does the work. The diagram shows the track. The car has a mass of 500 kg and starts at rest at point A.

Side view of a roller coaster track. A car starts at rest at point A, 40 m high. The track drops to point B (0 m, ground level), rises to point C (25 m), drops to point D (5 m) and rises to point E (15 m). Heights are marked on a vertical axis from 0 to 40 m. 0 10 20 30 40 Height (m) A (40 m) B (0 m) C (25 m) D (5 m) E (15 m) car

As the car rolls down, its gravitational potential energy (stored energy due to height) changes into kinetic energy (energy of motion). As it climbs the next hill, kinetic energy changes back into potential energy. The total amount of energy stays the same, but friction with the track and air resistance turn a small part of it into thermal energy and sound along the way. That is why each hill on a real coaster must be lower than the first one.

Use the passage and PE = mgh, with g = 9.8\text{ m/s}^2.

Sensors on the coaster show that the car's kinetic energy at point B is 180,000 J. Which statement is best supported by this measurement and the passage?

Answer choices
Hint

First find the car's total energy at A. Then compare it with the kinetic energy measured at B, where the height is 0 m.

Question 8 of 10 · Chemical properties and reactions

Making Rock Candy

Rock candy is made by dissolving as much table sugar (sucrose) as possible in hot water and then letting the solution cool slowly. As the solution cools, sugar crystals grow on a string or stick. The graph shows the greatest mass of sugar that can dissolve in 100 g of water at different temperatures.

Line graph of the solubility of table sugar (sucrose), in grams per 100 g of water (y-axis, 0 to 500), versus water temperature in degrees Celsius (x-axis, 0 to 100). Sugar: 179 g at 0 degrees C, 204 g at 20 degrees C, 238 g at 40 degrees C, 287 g at 60 degrees C, 362 g at 80 degrees C, 487 g at 100 degrees C. 0 50 100 150 200 250 300 350 400 450 500 0 20 40 60 80 100 Water temperature (°C) Sugar dissolved (g per 100 g water)

A solution that holds the greatest possible amount of dissolved sugar at its temperature is saturated; any extra sugar stays undissolved as solid. A solution that holds less than that amount is unsaturated.

A student stirs 250 g of sugar into 100 g of water at 40 °C until no more will dissolve. Then she heats the mixture to 60 °C and stirs again.

Which statement correctly describes the mixture at each temperature?

Answer choices
Hint

Read the solubility at 40 °C and at 60 °C and compare each with 250 g.

Question 9 of 10 · Chemical properties and reactions

Pure water has a pH of 7. A sample from a lake harmed by acid rain is found to be 1,000 times more acidic than pure water.

What is the pH of the lake sample?

Answer choices
Hint

How many factors of 10 make 1,000? Each factor of 10 is one pH unit. Which way does pH move when acidity increases?

Question 10 of 10 · Energy: conservation, transformation, flow

Electromagnetic Waves at Home

Many everyday devices send or use electromagnetic (EM) waves. All EM waves travel through empty space at the same speed, about 3.0 \times 10^8 m/s. For any wave, speed equals frequency times wavelength: v = f\lambda. The higher the frequency of an EM wave, the more energy it carries.

DeviceType of EM waveFrequency (Hz)
AM radioRadio wave1.0 \times 10^{6}
Wi-Fi routerMicrowave5.0 \times 10^{9}
TV remote controlInfrared3.0 \times 10^{14}
Tanning lampUltraviolet9.0 \times 10^{14}
Dental X-ray machineX-ray3.0 \times 10^{18}

Visible light has frequencies between about 4.0 \times 10^{14} Hz (red) and 7.5 \times 10^{14} Hz (violet).

A weather radar sends out microwaves with a wavelength of 0.10 m. Use the speed of EM waves and the wave equation from the passage.

What is the frequency of the radar waves?

Answer choices
Hint

Solve v = fλ for f. Check the units: your answer must come out in hertz (1/s).