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Maria rode in a 24-kilometer road race. A GPS unit on her bicycle recorded how far she was from the starting line throughout the race. Partway through, she had to stop and fix a flat tire. Near the end, the course climbed a long hill to the finish line.
The graph shows her distance from the start during the 60 minutes of the race.
Speed can be found with the formula \text{speed} = \dfrac{\text{distance}}{\text{time}}. Average speed for a whole trip is the total distance divided by the total time, including any stops.
Click the part of the graph that shows the time when Maria had stopped to fix her flat tire.
Click on the figure to mark your answer (or focus it and use the arrow keys).
Hint
If she is not moving, what happens to her distance from the start as time goes by?
Step-by-step solution
The passage says Maria "had to stop and fix a flat tire." On a distance-time graph, a stop shows up as a flat (horizontal) segment, because time keeps passing but her distance from the start does not change.
Step by step:
Read the axes: time (minutes) across the bottom, distance from the start (km) up the side.
Check each segment. From 0 to 20 minutes, distance rises from 0 to 10 km, so she is moving.
From 20 to 30 minutes, the line stays at 10 km, flat. Her distance did not change for 10 minutes.
From 30 to 50 minutes and from 50 to 60 minutes the line rises again, so she is moving.
The correct region is the flat segment from 20 to 30 minutes at 10 km. A common wrong click is the gently sloping segment from 50 to 60 minutes: she was slow there (climbing the hill), but slow is not stopped.
Tip: On a distance-time graph, the slope is the speed. Flat means a speed of zero; steeper means faster.
Question 2 of 34 · Work, motion and forces
Fill inA Bike Race with a Flat Tire
Maria rode in a 24-kilometer road race. A GPS unit on her bicycle recorded how far she was from the starting line throughout the race. Partway through, she had to stop and fix a flat tire. Near the end, the course climbed a long hill to the finish line.
The graph shows her distance from the start during the 60 minutes of the race.
Speed can be found with the formula \text{speed} = \dfrac{\text{distance}}{\text{time}}. Average speed for a whole trip is the total distance divided by the total time, including any stops.
What was Maria's average speed for the whole 60-minute race, in kilometers per hour?
km/h
Type your answer in the box. Fractions like 3/4 are fine.
Hint
Use total distance ÷ total time, and remember that 60 minutes is 1 hour.
Step-by-step solution
Use the formula given in the passage: average speed = total distance ÷ total time, "including any stops."
Step by step:
Total distance: the last point on the graph is (60, 24), so she rode 24 km.
Total time: 60 minutes = 1 hour. The 10-minute stop counts, because it is part of the trip.
Check: if you leave out the stop, you get \dfrac{24}{50 \div 60} = 28.8 km/h, which is the average speed while moving, not for the whole race. And 24 ÷ 60 = 0.4 is the speed in kilometers per minute, not per hour.
Tip: Always check what units the question wants. Convert minutes to hours before dividing when the answer must be in km/h.
Question 3 of 34 · Work, motion and forces
Drop-downA Bike Race with a Flat Tire
Maria rode in a 24-kilometer road race. A GPS unit on her bicycle recorded how far she was from the starting line throughout the race. Partway through, she had to stop and fix a flat tire. Near the end, the course climbed a long hill to the finish line.
The graph shows her distance from the start during the 60 minutes of the race.
Speed can be found with the formula \text{speed} = \dfrac{\text{distance}}{\text{time}}. Average speed for a whole trip is the total distance divided by the total time, including any stops.
Complete the sentences based on the graph.
From 30 to 50 minutes, Maria's speed was kilometers per hour. This speed was her speed from 0 to 20 minutes.
Choose an answer from each menu.
Hint
Find the distance covered in each 20-minute interval, then change minutes to hours.
Step-by-step solution
Read the distance at the start and end of each interval from the labeled points.
30 to 50 minutes: the points are (30, 10) and (50, 22).
distance = 22 - 10 = 12 km; time = 20 min = \tfrac{1}{3} h
speed = \dfrac{12 \text{ km}}{\tfrac{1}{3} \text{ h}} = 36 km/h
0 to 20 minutes: the points are (0, 0) and (20, 10).
distance = 10 km in \tfrac{1}{3} h, so speed = 30 km/h
36 km/h is greater than 30 km/h. You can also see this on the graph: the 30–50 minute segment is steeper.
The answers are b1 = 36 and b2 = greater than.
Tip: On a distance-time graph, compare speeds by comparing steepness, then confirm with a calculation. Watch the units: 0.6 is the speed in km per minute.
Question 4 of 34 · Heredity and genetics
Fill inSickle Cells and Malaria
Hemoglobin is the protein in red blood cells that carries oxygen. One gene controls the type of hemoglobin a person makes. The gene has two common alleles: A (normal hemoglobin) and S (sickle hemoglobin). Every person inherits one allele from each parent.
AA: normal red blood cells.
AS (sickle-cell trait): usually healthy, and much less likely to die from malaria, a disease spread by mosquitoes.
SS (sickle-cell disease): many red blood cells bend into a sickle shape and block small blood vessels. Without modern medical care, many people with SS die young.
Researchers measured how common the S allele is in four regions.
Region
Malaria
Frequency of S allele (%)
Lowland Valley
Common
14
Coastal Plain
Common
11
Highland Plateau
Rare
2
Mountain Town
Rare
1
The frequency of an allele is the percent of all copies of the gene in a population that are that allele.
Two parents both have sickle-cell trait (genotype AS). What is the probability, as a percent, that their child will have sickle-cell disease?
%
Type your answer in the box. Fractions like 3/4 are fine.
Hint
Draw a Punnett square with A and S from each parent. Which genotype causes the disease?
Step-by-step solution
The passage says sickle-cell disease is genotype SS, and that "Every person inherits one allele from each parent."
Step by step:
Each AS parent passes on either A or S, each with a chance of 1 in 2.
Punnett square for AS × AS:
A
S
A
AA
AS
S
AS
SS
The four boxes are equally likely: AA, AS, AS, SS.
Only 1 of 4 boxes is SS: \tfrac{1}{4} = 0.25 = 25\%.
The answer is 25%.
Careful: 50% is the chance the child has sickle-cell trait (AS), and 75% is the chance the child has at least one A allele.
Tip: For any cross of two heterozygous parents (Aa × Aa), the genotype ratio is 1 : 2 : 1, so the chance of the homozygous recessive genotype is always 25%.
Question 5 of 34 · Evolution
Sickle Cells and Malaria
Hemoglobin is the protein in red blood cells that carries oxygen. One gene controls the type of hemoglobin a person makes. The gene has two common alleles: A (normal hemoglobin) and S (sickle hemoglobin). Every person inherits one allele from each parent.
AA: normal red blood cells.
AS (sickle-cell trait): usually healthy, and much less likely to die from malaria, a disease spread by mosquitoes.
SS (sickle-cell disease): many red blood cells bend into a sickle shape and block small blood vessels. Without modern medical care, many people with SS die young.
Researchers measured how common the S allele is in four regions.
Region
Malaria
Frequency of S allele (%)
Lowland Valley
Common
14
Coastal Plain
Common
11
Highland Plateau
Rare
2
Mountain Town
Rare
1
The frequency of an allele is the percent of all copies of the gene in a population that are that allele.
Sickle-cell disease (SS) is a serious illness, yet the S allele is fairly common in Lowland Valley. Which explanation best accounts for both of these facts?
Hint
Think about which genotype survives best where malaria is common, and what it passes to its children.
Step-by-step solution
Two findings seem to conflict: SS is harmful, but S stays common where malaria is common (14% and 11%) and is rare where malaria is rare (2% and 1%). The passage gives the key: people with AS are "much less likely to die from malaria."
Step by step:
Where malaria is common, AA people are more likely to die of malaria, and SS people are likely to die of sickle-cell disease.
AS people survive best, so they have more children.
Each AS parent passes the S allele to about half of their children, so the S allele stays in the population.
Where malaria is rare, AS has no advantage, so S is not kept common. That fits the table.
The correct answer is A: this is natural selection favoring the carriers (heterozygotes).
Tip: Natural selection acts on traits that already exist. An environment does not create the mutations it needs; it changes which individuals survive and reproduce.
Question 6 of 34 · Evolution
Sickle Cells and Malaria
Hemoglobin is the protein in red blood cells that carries oxygen. One gene controls the type of hemoglobin a person makes. The gene has two common alleles: A (normal hemoglobin) and S (sickle hemoglobin). Every person inherits one allele from each parent.
AA: normal red blood cells.
AS (sickle-cell trait): usually healthy, and much less likely to die from malaria, a disease spread by mosquitoes.
SS (sickle-cell disease): many red blood cells bend into a sickle shape and block small blood vessels. Without modern medical care, many people with SS die young.
Researchers measured how common the S allele is in four regions.
Region
Malaria
Frequency of S allele (%)
Lowland Valley
Common
14
Coastal Plain
Common
11
Highland Plateau
Rare
2
Mountain Town
Rare
1
The frequency of an allele is the percent of all copies of the gene in a population that are that allele.
A researcher predicts that if malaria were completely eliminated from Lowland Valley, the S allele would slowly become less common there over many generations. Which evidence from the table best supports this prediction?
Hint
Look for a comparison in the table that shows what happens to S when malaria is not around.
Step-by-step solution
The prediction is about what happens to S without malaria. The best support is data from places where malaria is rare.
Step by step:
Regions where malaria is common: Lowland Valley 14%, Coastal Plain 11%.
Regions where malaria is rare: Highland Plateau 2%, Mountain Town 1%.
So S is far less common where malaria is rare. If Lowland Valley lost its malaria, it would become more like those regions, and S would be expected to decline.
The other choices are true statements, but none of them compares regions with and without malaria.
The correct answer is B.
Tip: Evidence supports a claim only if it is about the same variable as the claim. Ask: "Does this fact actually connect the cause (malaria) to the effect (S frequency)?"
Question 7 of 34 · Work, motion and forces
A soccer player kicks a ball with a mass of 0.45 kg. During the kick, the player's foot pushes on the ball with an average force of 90 N.
Using Newton's second law, F = m \times a, what is the average acceleration of the ball during the kick?
Hint
Rearrange the formula to solve for a: divide the force by the mass.
Step-by-step solution
Newton's second law says F = m \times a. To find acceleration, divide both sides by the mass: a = \dfrac{F}{m}.
Why the others are wrong: 40.5 comes from multiplying force by mass, 0.005 from dividing mass by force (upside down), and 89.55 from subtracting.
Tip: A light object pushed by a large force gets a large acceleration. If your answer is tiny, you probably divided the wrong way.
Question 8 of 34 · Earth and its system components
Hot spotRock Layers at Red Bluff
A geology class visited Red Bluff, a road cut that exposes rock layers. Their teacher drew the cross section below.
The teacher reminded the class of three ideas geologists use to put past events in order:
Superposition: in undisturbed sedimentary layers, the oldest layer is at the bottom and the youngest is at the top.
Cross-cutting relationships: a feature that cuts across rock layers, such as a fault or a body of igneous rock, is younger than every layer it cuts.
Erosion surfaces: a wavy, uneven boundary between layers shows a time when rock at the surface was worn away by erosion before new layers were deposited on top of it.
Click the rock layer or feature in the cross section that formed most recently (is the youngest).
Click on the figure to mark your answer (or focus it and use the arrow keys).
Hint
Superposition tells you which layer is youngest, but cross-cutting relationships can beat that. What cuts through everything?
Step-by-step solution
Use the principles listed in the passage.
Step by step:
Superposition: among the layers, D is on top, so D is the youngest layer.
Cross-cutting: "a feature that cuts across rock layers … is younger than every layer it cuts."
The fault cuts A, B and C, but it stops at the erosion surface and does not cut D. So the fault is older than D.
The igneous dike E cuts through A, B, C and D and reaches the surface. So E is younger than D.
Nothing cuts E, so E is the youngest feature.
The correct answer is the igneous dike, E. Clicking layer D is the most common error: D is the youngest layer, but the dike had to form after D was already there in order to cut through it.
Tip: On rock-layer diagrams, list every feature, then ask "What does it cut?" A feature can only cut rocks that already existed.
Question 9 of 34 · Earth and its system components
Drop-downRock Layers at Red Bluff
A geology class visited Red Bluff, a road cut that exposes rock layers. Their teacher drew the cross section below.
The teacher reminded the class of three ideas geologists use to put past events in order:
Superposition: in undisturbed sedimentary layers, the oldest layer is at the bottom and the youngest is at the top.
Cross-cutting relationships: a feature that cuts across rock layers, such as a fault or a body of igneous rock, is younger than every layer it cuts.
Erosion surfaces: a wavy, uneven boundary between layers shows a time when rock at the surface was worn away by erosion before new layers were deposited on top of it.
Complete the sentence based on the cross section.
The fault formed and .
Choose an answer from each menu.
Hint
Which layers does the fault cut, and which layer does it NOT cut?
Step-by-step solution
Apply cross-cutting relationships to the fault.
Step by step:
The fault cuts layers A, B and C, so it is younger than C. It formed after layer C was deposited.
The fault stops at the wavy erosion surface and does not cut layer D. If D had been there already, the crack would run through it too. So the fault formed before layer D was deposited.
The dike E cuts layer D, so the dike is younger than D, and therefore younger than the fault. The fault did not form after the dike.
The answers are b1 = after layer C was deposited and b2 = before layer D was deposited.
Tip: A feature is "sandwiched" in time: younger than the youngest layer it cuts, older than the oldest layer that lies undisturbed across it.
Question 10 of 34 · Earth and its system components
Rock Layers at Red Bluff
A geology class visited Red Bluff, a road cut that exposes rock layers. Their teacher drew the cross section below.
The teacher reminded the class of three ideas geologists use to put past events in order:
Superposition: in undisturbed sedimentary layers, the oldest layer is at the bottom and the youngest is at the top.
Cross-cutting relationships: a feature that cuts across rock layers, such as a fault or a body of igneous rock, is younger than every layer it cuts.
Erosion surfaces: a wavy, uneven boundary between layers shows a time when rock at the surface was worn away by erosion before new layers were deposited on top of it.
Which sequence of events best explains the wavy boundary between layer C and layer D?
Hint
Reread idea 3 in the passage about erosion surfaces. What had to happen to layer C before D could sit on it?
Step-by-step solution
The passage says a wavy, uneven boundary "shows a time when rock at the surface was worn away by erosion before new layers were deposited on top of it."
Step by step:
Superposition: A, B and C were deposited first, in that order (oldest at the bottom).
The fault cuts A–C but stops at the wavy line, so faulting happened after C.
The wavy line means the top of the rock (including the top of C and the fault) was worn away by erosion.
Only after that was layer D deposited on the eroded surface.
The correct answer is C.
Tip: Erosion surfaces are "missing time" in the rock record. Rock that was once there was removed before the next layer was laid down.
Question 11 of 34 · Life functions and energy intake
Sugar and Rising Dough
A baker wanted to know how the amount of sugar in bread dough affects yeast. Yeast are single-celled fungi. They break down sugar to get energy, and in the process they give off a gas that makes dough rise.
The baker set up five flasks. Each flask held 100 mL of water at 35 °C and 7 g of dry yeast. She stirred a different mass of sugar into each flask: 0, 5, 10, 20 or 40 grams. She stretched an identical balloon over the mouth of each flask, waited 30 minutes, and then measured the volume of gas in each balloon.
A baking guide notes that when sugar is dissolved at a very high concentration, water tends to move out of yeast cells by osmosis, from the side with more water to the side with less water.
Which of these was a controlled variable in the baker's experiment?
Hint
A controlled variable is kept the same in every flask.
Step-by-step solution
A controlled variable is something kept the same for every group so that it cannot affect the results.
Step by step:
The passage says "Each flask held 100 mL of water at 35 °C." The water temperature was the same in every flask, so it is controlled.
The mass of sugar (0, 5, 10, 20 or 40 g) was changed on purpose. That is the independent variable.
The volume of gas in each balloon was measured as the result. That is the dependent variable.
The number of yeast cells at the end was never measured, so it is not one of the experiment's variables.
The correct answer is C, the temperature of the water.
Tip: Look for the words each, same and identical in an experiment description; they point to controlled variables.
Question 12 of 34 · Life functions and energy intake
Sugar and Rising Dough
A baker wanted to know how the amount of sugar in bread dough affects yeast. Yeast are single-celled fungi. They break down sugar to get energy, and in the process they give off a gas that makes dough rise.
The baker set up five flasks. Each flask held 100 mL of water at 35 °C and 7 g of dry yeast. She stirred a different mass of sugar into each flask: 0, 5, 10, 20 or 40 grams. She stretched an identical balloon over the mouth of each flask, waited 30 minutes, and then measured the volume of gas in each balloon.
A baking guide notes that when sugar is dissolved at a very high concentration, water tends to move out of yeast cells by osmosis, from the side with more water to the side with less water.
Which statement best explains why the flask with 40 g of sugar produced less gas than the flask with 20 g?
Hint
The 40 g flask had more food than any other flask. Use the baking guide's note at the end of the passage.
Step-by-step solution
Read the data first: gas rose from 5 mL (0 g) to a peak of 95 mL (20 g), then fell to 60 mL (40 g). The 40 g flask had the most sugar, so the yeast did not run out of food.
The passage gives the key idea: at a very high sugar concentration, "water tends to move out of yeast cells by osmosis."
Step by step:
At 40 g the sugar solution is very concentrated, so there is less free water outside the cells than inside.
Water moves out of the yeast cells, and the dried-out cells cannot carry out their life processes as fast.
Slower activity means less sugar broken down and less gas given off.
The yeast were still active (60 mL is far more than the 5 mL with no sugar), so they were slowed, not all killed.
The correct answer is B.
Tip: When a graph rises and then falls, look in the passage for a second factor that becomes important at high values.
Question 13 of 34 · Life functions and energy intake
Drop-downSugar and Rising Dough
A baker wanted to know how the amount of sugar in bread dough affects yeast. Yeast are single-celled fungi. They break down sugar to get energy, and in the process they give off a gas that makes dough rise.
The baker set up five flasks. Each flask held 100 mL of water at 35 °C and 7 g of dry yeast. She stirred a different mass of sugar into each flask: 0, 5, 10, 20 or 40 grams. She stretched an identical balloon over the mouth of each flask, waited 30 minutes, and then measured the volume of gas in each balloon.
A baking guide notes that when sugar is dissolved at a very high concentration, water tends to move out of yeast cells by osmosis, from the side with more water to the side with less water.
Complete the sentence.
The yeast release energy from sugar through , a process that gives off gas, which makes the balloons and bread dough expand.
Choose an answer from each menu.
Hint
Yeast are fungi, not plants. Which gas bubbles out of rising dough and fizzy drinks?
Step-by-step solution
The passage says yeast "break down sugar to get energy, and in the process they give off a gas." In the flasks, each closed off by a balloon stretched over its mouth, oxygen is limited, so yeast do this through fermentation, a kind of cellular respiration that does not need oxygen.
Step by step:
Breaking down sugar to release energy is cellular respiration; in yeast without much oxygen it is called fermentation.
Fermentation in yeast turns sugar into alcohol (ethanol) and carbon dioxide.
The carbon dioxide gas fills the balloons and, in bread, makes bubbles that cause dough to rise.
The answers are b1 = fermentation and b2 = carbon dioxide.
Tip: Photosynthesis uses carbon dioxide and makes oxygen and sugar; respiration and fermentation use sugar and release carbon dioxide. Keep the directions straight.
Question 14 of 34 · Heredity and genetics
Each body cell of a dog contains 78 chromosomes. Sperm and egg cells are made by meiosis, and a puppy forms when one sperm joins one egg.
How many chromosomes are in each sperm cell of a dog?
Hint
The puppy's body cells must end up with the normal number after sperm and egg join.
Step-by-step solution
Meiosis makes sex cells (sperm and eggs) with half the number of chromosomes of a body cell, so that when a sperm and an egg join, the offspring has the full number again.
Step by step:
Body cell: 78 chromosomes (39 pairs).
Meiosis halves the number: 78 \div 2 = 39.
Check with fertilization: sperm (39) + egg (39) = 78, the normal number for a puppy's body cells ✓
The correct answer is B, 39.
If sperm had 78, the puppy would have 156 chromosomes, double the normal number, and the number would keep doubling every generation.
Tip: Mitosis keeps the chromosome number the same (body growth and repair); meiosis halves it (sex cells).
Question 15 of 34 · Work, motion and forces
Fill inPushing a Crate up a Ramp
Two movers need to load a crate that weighs 600 newtons (N) onto a truck bed 1.0 meter above the ground. Instead of lifting the crate straight up, they push it up a ramp 4.0 meters long. A force meter shows that they must push with a steady force of 200 N along the ramp to slide the crate up at a constant speed.
Useful formulas:
Work:W = F \times d (force times the distance moved in the direction of the force; 1 newton-meter = 1 joule, J)
Efficiency:\text{efficiency} = \dfrac{\text{useful work output}}{\text{work input}} \times 100\%
The useful work output is the work needed to lift the crate straight up onto the truck bed. The work input is the work the movers actually do pushing the crate along the ramp.
How much work, in joules, do the movers do pushing the crate all the way up the ramp?
J
Type your answer in the box. Fractions like 3/4 are fine.
Hint
Work = force × distance. Use the force the movers push with and the distance along the ramp.
Step-by-step solution
Use the work formula from the passage, W = F \times d, with the force the movers actually apply and the distance the crate moves in the direction of that force.
Step by step:
Force: the movers push with 200 N along the ramp.
Distance: the crate moves the full ramp length, 4.0 m, in the direction of the push.
Common errors: 600 × 1.0 = 600 J is the work to lift the crate straight up (the useful output), not the work the movers do on the ramp; 200 × 1.0 = 200 J mixes the push force with the height.
Tip: In W = F × d, the force and the distance must point the same way. A push along the ramp goes with the ramp's length; the weight goes with the vertical height.
Question 16 of 34 · Work, motion and forces
Fill inPushing a Crate up a Ramp
Two movers need to load a crate that weighs 600 newtons (N) onto a truck bed 1.0 meter above the ground. Instead of lifting the crate straight up, they push it up a ramp 4.0 meters long. A force meter shows that they must push with a steady force of 200 N along the ramp to slide the crate up at a constant speed.
Useful formulas:
Work:W = F \times d (force times the distance moved in the direction of the force; 1 newton-meter = 1 joule, J)
Efficiency:\text{efficiency} = \dfrac{\text{useful work output}}{\text{work input}} \times 100\%
The useful work output is the work needed to lift the crate straight up onto the truck bed. The work input is the work the movers actually do pushing the crate along the ramp.
What is the efficiency of the ramp, as a percent?
%
Type your answer in the box. Fractions like 3/4 are fine.
Hint
First find the useful work output (lifting straight up) and the work input (pushing along the ramp).
Step-by-step solution
Efficiency compares the useful work output with the work input, using the formula in the passage.
Step by step:
Useful work output = work to lift the crate straight up: weight × height:
W_{out} = 600 \text{ N} \times 1.0 \text{ m} = 600 \text{ J}
Work input = work the movers do along the ramp: push × ramp length:
W_{in} = 200 \text{ N} \times 4.0 \text{ m} = 800 \text{ J}
Watch out for the upside-down fraction: \dfrac{800}{600} \times 100\% \approx 133\% is impossible, because no real machine puts out more work than is put in.
Tip: Efficiency is always output over input, and for real machines it is always less than 100%.
Question 17 of 34 · Energy: conservation, transformation, flow
Pushing a Crate up a Ramp
Two movers need to load a crate that weighs 600 newtons (N) onto a truck bed 1.0 meter above the ground. Instead of lifting the crate straight up, they push it up a ramp 4.0 meters long. A force meter shows that they must push with a steady force of 200 N along the ramp to slide the crate up at a constant speed.
Useful formulas:
Work:W = F \times d (force times the distance moved in the direction of the force; 1 newton-meter = 1 joule, J)
Efficiency:\text{efficiency} = \dfrac{\text{useful work output}}{\text{work input}} \times 100\%
The useful work output is the work needed to lift the crate straight up onto the truck bed. The work input is the work the movers actually do pushing the crate along the ramp.
The movers put 800 J of work into pushing the crate, but the crate gained only 600 J of energy from being raised. Which statement best accounts for the other 200 J?
Hint
Energy cannot be created or destroyed. What rubs against what as the crate slides?
Step-by-step solution
Two findings must be reconciled: work input (800 J) is larger than the useful output (600 J). The law of conservation of energy says energy is never destroyed, so the missing 200 J must have gone somewhere else.
Step by step:
The passage says the movers slide the crate up the ramp. Sliding surfaces rub, which causes friction.
Friction converts kinetic (motion) energy into thermal energy: the crate bottom and ramp surface warm slightly, and a little energy becomes sound.
Energy check: 600 \text{ J (raised crate)} + 200 \text{ J (heat and sound from friction)} = 800 \text{ J} ✓
The correct answer is D.
Tip: Whenever a machine's output is less than its input, the "lost" energy has usually been transformed into heat by friction. It is not destroyed.
Question 18 of 34 · Structure of the cosmos
Hunting for Planets
Astronomers can find planets around distant stars by watching for a transit. When a planet passes in front of its star, it blocks a tiny part of the star's light, and the star looks slightly dimmer for a few hours. A planet makes one transit each time it completes one orbit around its star.
A space telescope measured the brightness of the star Vela-7 for 40 days. Two planets, b and c, were found.
Two facts help astronomers interpret data like these:
A larger planet blocks more light, so it makes a deeper dip. The depth of the dip depends on the planet's size (diameter), not on its mass.
Planets that orbit farther from their star take longer to complete one orbit.
Based on the graph, how long does it take planet b to complete one orbit around Vela-7?
Hint
One orbit = the time from one b dip to the next b dip.
Step-by-step solution
The passage says a planet "makes one transit each time it completes one orbit." So the time between two neighboring dips from the same planet is one orbit.
Step by step:
Find the dips labeled b: they are at days 4, 14, 24 and 34.
Time between neighboring b dips: 14 - 4 = 10, 24 - 14 = 10, 34 - 24 = 10 days.
The spacing is always 10 days, so one orbit takes 10 days.
The correct answer is B, 10 days.
4 days is just the time of the first dip, 1 is the drop in brightness (100% − 99% = 1%), and 24 days is the spacing of the c dips (days 8 and 32), which belongs to planet c.
Tip: For anything that repeats, the period is the spacing between repeats, not the position of the first one.
Question 19 of 34 · Structure of the cosmos
Select allHunting for Planets
Astronomers can find planets around distant stars by watching for a transit. When a planet passes in front of its star, it blocks a tiny part of the star's light, and the star looks slightly dimmer for a few hours. A planet makes one transit each time it completes one orbit around its star.
A space telescope measured the brightness of the star Vela-7 for 40 days. Two planets, b and c, were found.
Two facts help astronomers interpret data like these:
A larger planet blocks more light, so it makes a deeper dip. The depth of the dip depends on the planet's size (diameter), not on its mass.
Planets that orbit farther from their star take longer to complete one orbit.
Which conclusions about the two planets are supported by the graph and the passage? Select all that apply.
Select all that apply.
Hint
Use only the two facts at the end of the passage: dip depth tells size; time between dips tells orbit length.
Step-by-step solution
Check each claim against the data and the two facts the passage gives.
Step by step:
Dip depth: b dips to 99.0% (1% of the light blocked); c dips to 99.75% (0.25% blocked). "A larger planet blocks more light," so planet b is larger than planet c. A is supported.
Orbit time: b repeats every 10 days; c repeats every 24 days (days 8 and 32). "Planets that orbit farther … take longer," so planet c orbits farther from the star. B is supported.
Mass: the passage says dip depth depends on size, "not on its mass." So the graph cannot tell us which planet is more massive. D is not supported.
Temperature was never measured. If anything, c is farther from the star, so it is probably cooler, not hotter. C is not supported.
Only planet b repeats every 10 days, so E is false.
The correct answers are A and B.
Tip: In select-all questions, judge every choice on its own. Reject anything the data cannot measure, even if it sounds reasonable.
Question 20 of 34 · Evolution
Fill inFinches in a Drought
Isla Seca is a small island where medium ground finches eat seeds. Finches with deeper (taller) beaks can crack large, hard seeds. Finches with shallower beaks are better at picking up small, soft seeds. Beak depth varies from bird to bird.
In Year 1, researchers measured the beak depth of 1,200 finches on the island. In Year 2, a severe drought struck. Plants produced few seeds, and the small, soft seeds were quickly eaten up. Mostly large, hard seeds were left. By Year 3, only 180 of the finches were still alive. The researchers measured the beaks of the survivors.
Calculate the mean (average) beak depth of the Year 3 survivors. Treat every bird in a bar as having exactly that beak depth (for example, all birds in the 8 mm bar have a beak depth of 8 mm).
mm
Type your answer in the box. Fractions like 3/4 are fine.
Hint
Multiply each beak depth by its percent (as a decimal), then add the results.
Step-by-step solution
When data are given as percents of a group, the mean is a weighted average: multiply each value by the fraction of birds that have it, then add.
Survivors (red bars): 7 mm 0%, 8 mm 15%, 9 mm 35%, 10 mm 35%, 11 mm 15% (total 100%).
Compare: the Year 1 mean was 7(0.10) + 8(0.30) + 9(0.35) + 10(0.20) + 11(0.05) = 8.8 mm, so the average beak got about 0.7 mm deeper. A common mistake is averaging the five depths (7 + 8 + 9 + 10 + 11) ÷ 5 = 9, which ignores how many birds are in each bar.
Tip: If groups are different sizes, a plain average of the categories is wrong. Weight each value by how many (or what percent) are in it.
Question 21 of 34 · Evolution
Drag and dropFinches in a Drought
Isla Seca is a small island where medium ground finches eat seeds. Finches with deeper (taller) beaks can crack large, hard seeds. Finches with shallower beaks are better at picking up small, soft seeds. Beak depth varies from bird to bird.
In Year 1, researchers measured the beak depth of 1,200 finches on the island. In Year 2, a severe drought struck. Plants produced few seeds, and the small, soft seeds were quickly eaten up. Mostly large, hard seeds were left. By Year 3, only 180 of the finches were still alive. The researchers measured the beaks of the survivors.
Drag each event into the correct order to explain how natural selection changed the finch population on Isla Seca.
Tap a tile, then tap a box to place it.
Hint
Natural selection starts with variation that already exists and ends with a change in the next generation.
Step-by-step solution
Natural selection follows the same pattern every time: variation → environmental pressure → unequal survival → reproduction → change in the population.
Step by step:
Variation: "Beak depth varies from bird to bird," and offspring tend to inherit their parents' beak depth.
Pressure: the drought meant that "Mostly large, hard seeds were left."
Unequal survival: birds with deeper beaks could crack those seeds, so more of them survived. The graph shows this: no 7 mm birds survived, while the share of 10 mm and 11 mm birds rose.
Reproduction: survivors breed and pass on the genes for deep beaks.
Change: the next generation has a greater average beak depth.
Order: variation → mostly hard seeds remain → deep-beaked birds survive → survivors pass on genes → deeper average beak.
Tip: Individuals do not evolve during their lifetimes. Populations change because some individuals survive and reproduce more than others.
Question 22 of 34 · Evolution
Finches in a Drought
Isla Seca is a small island where medium ground finches eat seeds. Finches with deeper (taller) beaks can crack large, hard seeds. Finches with shallower beaks are better at picking up small, soft seeds. Beak depth varies from bird to bird.
In Year 1, researchers measured the beak depth of 1,200 finches on the island. In Year 2, a severe drought struck. Plants produced few seeds, and the small, soft seeds were quickly eaten up. Mostly large, hard seeds were left. By Year 3, only 180 of the finches were still alive. The researchers measured the beaks of the survivors.
The researchers want to confirm that beak depth is inherited (passed from parents to offspring) rather than caused only by what a bird eats. Which study would best test this?
Hint
To show a trait is inherited, compare parents and offspring while keeping diet the same.
Step-by-step solution
To test whether a trait is inherited, you need to compare parents with their offspring while keeping other causes, such as diet, the same.
Step by step:
The question gives two possible causes of beak depth: genes (inheritance) and food.
Choice C raises chicks on the same food, so diet is controlled.
If chicks of deep-beaked parents still grow deep beaks, and chicks of shallow-beaked parents grow shallow ones, the difference must come from the parents, which means the trait is inherited.
The other studies never compare parents with offspring, so they cannot show inheritance.
The correct answer is C.
Tip: A good test changes or compares only the variable in question (here, parentage) and controls the alternative explanation (here, diet).
Question 23 of 34 · Work, motion and forces
Momentum is found with the formula p = m \times v (mass × velocity).
Vehicle
Mass (kg)
Speed (m/s)
Car
1,200
15
City bus
9,000
2.0
Which statement correctly compares the momentum of the two vehicles?
Hint
Calculate both momentums before choosing. Do not judge by speed or size alone.
The correct answer is C: they have equal momentum, 18,000 kg·m/s each.
The car is faster and the bus is heavier, and here the two effects balance exactly. Choices A and B each look at only one factor. Choice D is wrong because the momentum formula uses only mass and velocity, not force.
Tip: When a formula multiplies two quantities, a big value of one can be balanced by a small value of the other. Always calculate before you compare.
Question 24 of 34 · Chemical properties and reactions
Baking Soda and Vinegar
A student studied the reaction between baking soda and vinegar, two common kitchen ingredients.
baking soda + acetic acid (in vinegar) → sodium acetate + water + carbon dioxide
NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂
For each trial, she poured 100 g of vinegar into a plastic bottle and lowered a small paper cup holding 5.0 g of baking soda into the bottle without letting the two touch. She weighed the whole setup, including the bottle's screw cap, and measured the temperature of the vinegar. Then she tipped the bottle so the baking soda fell into the vinegar.
Trial A: the bottle was left open (the cap sat on the scale beside it).
Trial B: the bottle was sealed with the screw cap before tipping.
Trial
Mass before (g)
Mass after (g)
Temperature before (°C)
Temperature after (°C)
A (open)
260.0
257.4
21.0
18.5
B (sealed)
260.0
260.0
21.0
18.5
In both trials the mixture fizzed strongly, the white powder disappeared, and the liquid stayed clear and colorless.
Looking only at Trial A, a classmate concludes that mass was destroyed in the reaction. Which statement best uses the results of both trials to evaluate this conclusion?
Hint
What is different about Trial B? Which product of the reaction is a gas?
Step-by-step solution
The two trials seem to disagree: Trial A lost mass, but Trial B did not. The difference between them is whether the bottle was open or sealed.
Step by step:
Trial A (open): 260.0 - 257.4 = 2.6 g lost.
Trial B (sealed): 260.0 g before and 260.0 g after, with no change, even though the same reaction happened (it fizzed the same way).
The equation shows one product is carbon dioxide gas (CO₂). In the open bottle, the gas escaped into the air, so the scale no longer counted it. In the sealed bottle, the gas was trapped and still weighed.
So the mass was not destroyed; it left the bottle as gas. This agrees with the law of conservation of mass.
The correct answer is B.
Tip: If mass seems to disappear (or appear) in a reaction, check whether a gas could have escaped (or entered). A closed system always keeps the same total mass.
Question 25 of 34 · Chemical properties and reactions
Select allBaking Soda and Vinegar
A student studied the reaction between baking soda and vinegar, two common kitchen ingredients.
baking soda + acetic acid (in vinegar) → sodium acetate + water + carbon dioxide
NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂
For each trial, she poured 100 g of vinegar into a plastic bottle and lowered a small paper cup holding 5.0 g of baking soda into the bottle without letting the two touch. She weighed the whole setup, including the bottle's screw cap, and measured the temperature of the vinegar. Then she tipped the bottle so the baking soda fell into the vinegar.
Trial A: the bottle was left open (the cap sat on the scale beside it).
Trial B: the bottle was sealed with the screw cap before tipping.
Trial
Mass before (g)
Mass after (g)
Temperature before (°C)
Temperature after (°C)
A (open)
260.0
257.4
21.0
18.5
B (sealed)
260.0
260.0
21.0
18.5
In both trials the mixture fizzed strongly, the white powder disappeared, and the liquid stayed clear and colorless.
Which observations are among the standard signs that a chemical reaction (a new substance forming) took place? Select all that apply.
Select all that apply.
Hint
Signs of a chemical change include a gas forming and a temperature change that happens on its own.
Step-by-step solution
Evidence of a chemical change is a sign that a new substance formed. Common signs are gas bubbles, a change in temperature that happens on its own, a color change, light, or a new solid forming.
Step by step:
Bubbles of gas formed (A): the fizzing is a new substance, carbon dioxide, being produced. Evidence ✓
The temperature dropped by itself (B): the mixture went from 21.0 °C to 18.5 °C with no ice or cooling. Breaking and forming chemical bonds absorbed energy. An unexpected temperature change is one of the standard signs ✓ (some solids also change temperature when they simply dissolve, so it is strongest together with other signs such as the fizzing).
The liquid stayed clear and colorless (C): this is the absence of a color change, so it is not evidence of anything new.
The sealed bottle's mass stayed the same (D): mass is conserved in every physical and chemical change, so this does not show a reaction.
The white powder disappeared (E): a powder also disappears when it simply dissolves (like sugar in water), which is a physical change. On its own, this does not prove a new substance formed.
The correct answers are A and B.
Tip: Learn the standard signs of a new substance: gas forming, an unexpected temperature change, a color change, light, or a new solid forming. Observations that are not on that list, such as a powder disappearing (which also happens when it simply dissolves) or mass staying the same, are not signs of a chemical change.
Question 26 of 34 · Chemical properties and reactions
Baking Soda and Vinegar
A student studied the reaction between baking soda and vinegar, two common kitchen ingredients.
baking soda + acetic acid (in vinegar) → sodium acetate + water + carbon dioxide
NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂
For each trial, she poured 100 g of vinegar into a plastic bottle and lowered a small paper cup holding 5.0 g of baking soda into the bottle without letting the two touch. She weighed the whole setup, including the bottle's screw cap, and measured the temperature of the vinegar. Then she tipped the bottle so the baking soda fell into the vinegar.
Trial A: the bottle was left open (the cap sat on the scale beside it).
Trial B: the bottle was sealed with the screw cap before tipping.
Trial
Mass before (g)
Mass after (g)
Temperature before (°C)
Temperature after (°C)
A (open)
260.0
257.4
21.0
18.5
B (sealed)
260.0
260.0
21.0
18.5
In both trials the mixture fizzed strongly, the white powder disappeared, and the liquid stayed clear and colorless.
Based on the temperature data, which statement correctly describes the reaction between baking soda and vinegar?
Hint
Did the mixture get warmer or colder? Which way did heat flow?
Step-by-step solution
Read the temperature columns: in both trials the temperature fell from 21.0 °C to 18.5 °C, a drop of 2.5 °C.
Step by step:
The mixture got colder even though nothing cooled it.
That means the reaction absorbed thermal energy from the liquid and its surroundings.
A reaction that absorbs energy is endothermic. (A reaction that releases energy and warms its surroundings is exothermic.)
The correct answer is A.
Choice D is a common trap: reactions do not "release cold." Cold is simply less thermal energy, and a temperature drop means energy was taken in. Choice B confuses giving off a gas with giving off heat.
Tip: Endo = energy goes in (surroundings get colder). Exo = energy goes out (surroundings get warmer).
Question 27 of 34 · Human body and health
A sports scientist measured a runner's core body temperature and sweat rate during a 90-minute run on a warm day.
Time (minutes)
Core body temperature (°C)
Sweat rate (liters per hour)
0
37.0
0.2
30
38.1
1.0
60
38.5
1.4
90
38.6
1.5
Sweat cools the body as it evaporates from the skin. Which statement is best supported by the data?
Hint
Look at how much the temperature rose in each 30-minute period, and what sweat rate was doing at the same time.
Step-by-step solution
Read both columns and look at the changes in each 30-minute period.
Step by step:
Temperature rises: 0–30 min: +1.1 °C; 30–60 min: +0.4 °C; 60–90 min: +0.1 °C. The rise gets smaller each time.
Sweat rate rises at the same time: 0.2 → 1.0 → 1.4 → 1.5 L/h.
As the body heats up, it sweats more; the extra evaporation removes heat, so the temperature levels off near 38.6 °C.
A response that works against a change and brings the body back toward balance is negative feedback, a key part of homeostasis.
The correct answer is C.
Tip: Negative feedback reduces a change (sweating when hot, shivering when cold). Positive feedback makes a change bigger and is much rarer in the body.
Question 28 of 34 · Energy: conservation, transformation, flow
Hot spotHeating Ice in a Pot
A cook takes 500 g of ice at −20 °C out of a freezer, puts it in a pot, and heats it on a stove burner that supplies energy at a steady rate. A thermometer in the pot records the temperature every minute, and the cook stirs constantly so the temperature is the same throughout the pot.
Click the part of the graph that shows when the ice is melting.
Click on the figure to mark your answer (or focus it and use the arrow keys).
Hint
Ice melts at 0 °C. While it melts, does the temperature change?
Step-by-step solution
Water ice melts at 0 °C. While a substance changes state, the energy added goes into breaking the attractions between particles, so the temperature stays constant until the change is complete.
Step by step:
0 to 1 minute: temperature rises from −20 °C to 0 °C. This is solid ice warming up, not melting yet.
1 to 9 minutes: the line is flat at 0 °C. Energy is still being added, but the temperature does not rise, because the ice is melting.
9 to 19 minutes: liquid water warms from 0 °C to 100 °C.
19 to 40 minutes: flat at 100 °C, where the water is boiling.
The correct region is the flat segment at 0 °C, from 1 to 9 minutes. The flat segment at 100 °C is also a change of state, but it is boiling, not melting.
Tip: On a heating curve, sloped parts = one state warming up; flat parts = a change of state. Use the temperature of the flat part to tell melting (0 °C for water) from boiling (100 °C at sea level).
Question 29 of 34 · Energy: conservation, transformation, flow
Heating Ice in a Pot
A cook takes 500 g of ice at −20 °C out of a freezer, puts it in a pot, and heats it on a stove burner that supplies energy at a steady rate. A thermometer in the pot records the temperature every minute, and the cook stirs constantly so the temperature is the same throughout the pot.
Which statement about the energy the burner supplied is best supported by the graph?
Hint
The burner adds the same amount of energy every minute. So more minutes means more energy.
Step-by-step solution
The passage says the burner "supplies energy at a steady rate." That means the energy added during a stage is proportional to how long the stage lasts.
Step by step:
Melting (flat at 0 °C): from 1 to 9 minutes, so 9 - 1 = 8 minutes.
Warming the liquid from 0 °C to 100 °C: from 9 to 19 minutes, so 19 - 9 = 10 minutes.
10 minutes > 8 minutes, so warming the liquid water took more energy than melting the ice.
A flat line does not mean no energy was used. The burner was on the whole time; during melting, its energy went into changing the state instead of raising the temperature.
The correct answer is B.
Tip: With a steady energy source, time is a stand-in for energy. Compare stage lengths along the x-axis, not the size of the temperature change.
Question 30 of 34 · Structure of the cosmos
Scientists find a bison bone in a cave. Tests show the bone now contains 25% of the carbon-14 it had when the bison died. The half-life of carbon-14 is 5,730 years.
About how long ago did the bison die?
Hint
Count how many times you must cut 100% in half to reach 25%.
Step-by-step solution
A half-life is the time it takes for half of a radioactive substance to decay. After each half-life, the amount left is cut in half.
Step by step:
Start: 100% of the original carbon-14.
After 1 half-life: 50%.
After 2 half-lives: 25%. So 2 half-lives have passed.
Time: 2 \times 5{,}730 = 11{,}460 years.
The correct answer is B, 11,460 years.
5,730 years would leave 50%, and 17,190 years (3 half-lives) would leave 12.5%. Multiplying 5,730 by 25% (1,432.5) treats decay as a straight percentage, which is not how half-life works.
Tip: Make a quick halving table (100 → 50 → 25 → 12.5 …) and count the steps.
Question 31 of 34 · Organization of life: cells, tissues, organisms
Drag and dropMuscle Fibers in Athletes
Skeletal muscles are made of long muscle cells called muscle fibers. Fibers are grouped into bundles that form muscle tissue. Muscle tissue, together with nerves and blood vessels, forms a whole muscle, such as the thigh muscle. All the skeletal muscles together make up the muscular system.
There are two main types of muscle fiber:
Slow-twitch fibers are packed with mitochondria, the organelles that use oxygen to release energy from food. They can work for a long time without tiring.
Fast-twitch fibers have fewer mitochondria. They contract quickly and powerfully but tire fast.
Study 1 took small samples of thigh muscle from four groups of adults.
Group
Slow-twitch fibers (%)
Elite sprinters
25
Untrained adults
50
Middle-distance runners
60
Elite marathon runners
80
Study 2 followed 20 untrained adults through six months of endurance (long-distance) training. Their average percentage of slow-twitch fibers changed only from 49% to 51%, a difference the researchers judged too small to be meaningful. However, the number of mitochondria in their muscle fibers rose by about 40%.
Drag the parts of the body into order from smallest level of organization to largest.
Smallest → 1. → 2. → 3. → 4. → 5. → Largest
Tap a tile, then tap a box to place it.
Hint
Organelle → cell → tissue → organ → organ system. Match each item to one of these levels.
Step-by-step solution
Living things are organized in levels: organelle → cell → tissue → organ → organ system. The passage describes each level for muscle.
Step by step:
Mitochondrion: an organelle, a structure inside a cell ("the organelles that use oxygen").
Muscle fiber: "long muscle cells called muscle fibers." This is the cell level.
Muscle tissue: "Fibers are grouped into bundles that form muscle tissue."
Thigh muscle: tissue "together with nerves and blood vessels, forms a whole muscle", an organ.
Muscular system: "All the skeletal muscles together make up the muscular system."
Tip: Each level is built from the level below it. If one item is found inside another, it is the smaller level.
Question 32 of 34 · Organization of life: cells, tissues, organisms
Muscle Fibers in Athletes
Skeletal muscles are made of long muscle cells called muscle fibers. Fibers are grouped into bundles that form muscle tissue. Muscle tissue, together with nerves and blood vessels, forms a whole muscle, such as the thigh muscle. All the skeletal muscles together make up the muscular system.
There are two main types of muscle fiber:
Slow-twitch fibers are packed with mitochondria, the organelles that use oxygen to release energy from food. They can work for a long time without tiring.
Fast-twitch fibers have fewer mitochondria. They contract quickly and powerfully but tire fast.
Study 1 took small samples of thigh muscle from four groups of adults.
Group
Slow-twitch fibers (%)
Elite sprinters
25
Untrained adults
50
Middle-distance runners
60
Elite marathon runners
80
Study 2 followed 20 untrained adults through six months of endurance (long-distance) training. Their average percentage of slow-twitch fibers changed only from 49% to 51%, a difference the researchers judged too small to be meaningful. However, the number of mitochondria in their muscle fibers rose by about 40%.
A coach looks at Study 1 and claims: "Marathon training turns fast-twitch fibers into slow-twitch fibers." Which statement best evaluates the coach's claim using both studies?
Hint
Study 1 compares different people at one time. Study 2 follows the same people as they train. Which study actually tests the claim?
Step-by-step solution
The coach's claim is about a change caused by training. Only a study that follows the same people before and after training can test that.
Step by step:
Study 1 shows marathon runners have more slow-twitch fibers (80%) than untrained adults (50%) or sprinters (25%). But it measures different people once. It shows a correlation, not a cause. People born with more slow-twitch fibers may simply be the ones who succeed at marathons.
Study 2 actually trained people for six months. Their slow-twitch percentage barely changed (49% → 51%), which the researchers judged "too small to be meaningful."
Study 2 did find a real change: mitochondria rose by about 40%. Training improved the fibers' ability to use oxygen without changing their type.
So the evidence does not support the coach's claim.
The correct answer is A.
Tip: A comparison of different groups at one time shows a correlation. To show that X causes a change, look for a study that changes X and tracks the same individuals.
Question 33 of 34 · Energy flow in ecosystems
In a grassland food chain, energy passes from grass → grasshoppers → frogs → snakes. On average, only about 10% of the energy at one level is passed on to the next level.
If the grass stores 50,000 kilocalories (kcal) of energy, about how much of that energy reaches the snakes?
Hint
Count the steps between grass and snakes, and take 10% once for each step.
Step-by-step solution
The 10% rule: at each step up a food chain, only about one-tenth of the energy is passed on. The rest is used for life processes or lost as heat.
There are three steps from grass to snakes, so the answer is C, 50 kcal.
500 kcal is the energy that reaches the frogs (stopping one step early), and 5,000 kcal reaches the grasshoppers.
Tip: Count arrows, not organisms. Four organisms in a chain means three transfers, so multiply by 0.10 three times.
Question 34 of 34 · Earth systems and living things
In 1991, Mount Pinatubo in the Philippines erupted and sent about 15 million tons of sulfur dioxide gas high into the atmosphere. The gas formed tiny droplets that reflected some sunlight back into space. Over the next year, Earth's average surface temperature dropped by about 0.5 °C.
Which effect on living things is most likely to have followed from this eruption?
Hint
Less sunlight reached the ground and temperatures fell. How would that affect plants and farms?
Step-by-step solution
Follow the chain of cause and effect in the passage: eruption → sulfur dioxide droplets → less sunlight reaches the surface → cooler temperatures (about 0.5 °C) for about a year.
Step by step:
Plants need sunlight and warmth to grow. Less sunlight and cooler weather can shorten the growing season.
So the most likely effect is cooler, shorter growing seasons and lower harvests in some farming regions.
Choices B and D say the opposite of the passage (more sunlight, warmer temperatures).
Choice C is not connected: nothing in the passage mentions sea level, and a cooling would not raise it.
The correct answer is A.
Tip: For Earth-systems questions, trace each step: what changed in the atmosphere, how that changed sunlight or temperature, and how that change reaches living things.