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The circle graph shows how a hospital nurse spends a 12-hour shift.
How many hours of the shift does the nurse spend on charting?
Hint
The graph gives a percent. Find that percent of the whole shift.
Step-by-step solution
Find the Charting section: it is 25\% of the shift.
The whole shift is 12 hours.
Change the percent to a decimal: 25\% = 0.25.
Multiply by the whole:
0.25 \times 12 = 3
The nurse spends 3 hours charting.
Check:25\% is one-fourth, and one-fourth of 12 hours is 12 \div 4 = 3 ✓.
Tip: A circle graph section × the total gives the amount. Benchmark percents help you check fast: 50% is half, 25% is a fourth, 10% is a tenth.
Question 2 of 10 · Scatter plots and two-variable data
Hot spot
An ice cream shop recorded the daily high temperature and the number of cones it sold on 13 summer days.
Click the point that is an outlier: the day that does not fit the pattern of the other days.
Click on the figure to mark your answer (or focus it and use the arrow keys).
Hint
Describe the overall pattern first. Then look for a point that sits far away from where that pattern says it should be.
Step-by-step solution
Read the overall pattern from left to right. As the temperature goes up, the number of cones sold goes up. The points rise in a fairly narrow band: a positive trend.
Use the pattern to predict. On days near 70^\circ\text{F} to 74^\circ\text{F}, the shop sold about 70 to 80 cones (the points (70, 72) and (74, 80)).
Now look for a point far from that band. The point (72, 150) shows 150 cones on a 72^\circ day. That is about twice what the trend predicts, and it is as high as the points for 90^\circ to 94^\circ days.
So the outlier is the point (72, 150).
Check: Its neighbors are (70, 72) and (74, 80). A value of 150 between them breaks the pattern by about 70 cones; no other point is off the band by more than a few cones ✓
Tip: The highest point (97, 165) and the lowest point (62, 40) are the extremes, but they follow the trend. An outlier is a point far from the pattern, not simply the biggest or smallest value. (Maybe that day had a local festival!)
Question 3 of 10 · Bar graphs and circle graphs
The double bar graph shows the quarterly sales of two stores, in thousands of dollars.
By what percent did Store A's sales increase from Q1 to Q3?
Hint
Percent change = (new − old) ÷ old × 100%. Which quarter is the "old" value?
Divide by the original (Q1) value and convert to a percent:
\frac{30}{40} = 0.75 = 75\%
Store A's sales increased by 75%.
Check:40 + 75\% of 40 = 40 + 30 = 70 ✓
Tip: The units (thousands of dollars) cancel when you find a percent change, so you can work with the numbers on the scale directly. Always divide by the starting value.
Question 4 of 10 · Bar graphs and circle graphs
Fill in
The pictograph shows how many trees four volunteer groups planted in a city park.
How many trees did the four groups plant in all?
trees
Type your answer in the box. Fractions like 3/4 are fine.
Hint
You can count all the symbols first, then use the key once.
Step-by-step solution
Count the symbols in each row:
Group A: 5
Group B: 3.5
Group C: 6
Group D: 2.5
Total symbols: 5 + 3.5 + 6 + 2.5 = 17.
Each full symbol is 8 trees, so multiply:
17 \times 8 = 136
The groups planted 136 trees in all.
Check: Group by group: 40 + 28 + 48 + 20 = 136 ✓.
Tip: Adding the symbols first and multiplying once is faster and has fewer chances for error. Half symbols count as 0.5.
Question 5 of 10 · Dot plots, histograms and box plots
Drag and drop
A call-center worker recorded how many calls she handled each day for 11 days:
12, 7, 15, 9, 20, 11, 14, 9, 17, 13, 10
She wants to make a box plot. Drag the correct value into each box. Not every value is used.
Minimum
First quartile (Q_1)
Median
Third quartile (Q_3)
Maximum
7
20
Tap a tile, then tap a box to place it.
Hint
Put the numbers in order first. The median splits the list; each quartile is the median of one half.
Step-by-step solution
Order the data from least to greatest:
7,\ 9,\ 9,\ 10,\ 11,\ \mathbf{12},\ 13,\ 14,\ 15,\ 17,\ 20
Median: 11 values, so the middle is position 6: 12.
Q_1: median of the lower half (the 5 values below the median): 7, 9, \mathbf{9}, 10, 11 → 9.
Q_3: median of the upper half: 13, 14, \mathbf{15}, 17, 20 → 15.
Answers: Q_1 = 9, median = 12, Q_3 = 15.
Check: Each part of the box plot should hold about the same number of values: 7 to 9, 9 to 12, 12 to 15, 15 to 20 each contain 2 or 3 of the 11 values ✓.
Tip: Never take the middle of an unsorted list. Sorting first is the step students skip most often.
Question 6 of 10 · Scatter plots and two-variable data
Fill in
A running coach collected data from runners training for a 5K race. Let x be the number of weeks a runner has trained and y the runner's 5K time in minutes. The equation of the trend line for the data is
y = -0.4x + 31
According to the trend line, what is the predicted 5K time, in minutes, for a runner who has trained for 12 weeks?
minutes
Type your answer in the box. Fractions like 3/4 are fine.
Hint
Which variable stands for weeks? Substitute 12 for that letter and follow the order of operations.
Step-by-step solution
In the equation, x is the number of weeks. Substitute x = 12:
y = -0.4(12) + 31
Multiply first:
-0.4 \times 12 = -4.8
Then add:
y = -4.8 + 31 = 26.2
The predicted time is 26.2 minutes.
Check: The slope -0.4 means each week of training takes about 0.4 minute off. Twelve weeks: 12 \times 0.4 = 4.8 minutes off the starting 31 minutes, giving 26.2 ✓ A faster time after more training makes sense.
Tip: On the TI-30XS, type the whole expression with the negative key: (-)0.4×12+31enter. Use the (-) key for a negative number, not the subtraction key, at the start of an expression.
Question 7 of 10 · Bar graphs and circle graphs
Select all
A food-truck owner made this bar graph of weekend taco sales. Look carefully at the vertical axis.
The owner wants to post claims about the weekend on social media. Select all of the claims that the actual numbers support.
Select all that apply.
Hint
Read every value from the axis. Test each statement with the numbers, not with how the bars look.
Step-by-step solution
Values: Friday = 450, Saturday = 600, Sunday = 500. The axis starts at 400.
A — true.600 - 450 = 150 more tacos on Saturday.
B — false. Sunday's bar looks twice Friday's, but 500 \div 450 \approx 1.11. The visible parts are 100 and 50, which is why it looks double.
C — true. The axis starts at 400, so small differences look huge.
D — true. Percent more = \frac{600 - 500}{500} = \frac{100}{500} = 20\%.
E — false. One-fourth of 600 is 150, and Friday sold 450, which is three-fourths of Saturday.
Correct choices: A, C, and D.
Check D:500 \times 1.20 = 600 ✓.
Tip: A broken or non-zero axis is a classic GED trap. Ratios and percents must come from the axis values.
Question 8 of 10 · Dot plots, histograms and box plots
Drop-down
In a science class, students grew bean plants with and without fertilizer. The box plots show the plant heights after four weeks.
Choose the correct answer for each blank.
The median height with fertilizer is the median height without fertilizer.
The group with the greater range is .
The interquartile ranges of the two groups are .
Choose an answer from each menu.
Hint
Median = line in the box. Range = whisker end minus whisker end. IQR = right edge of box minus left edge.
Step-by-step solution
Blank 1 — medians. Fertilizer median = 24, none = 19. 24 - 19 = 5, so it is 5 cm greater than.
Blank 2 — ranges. Fertilizer: 33 - 14 = 19 cm. None: 30 - 10 = 20 cm. The no-fertilizer group has the greater range.
Blank 3 — IQRs. Fertilizer: 27 - 20 = 7 cm. None: 22 - 15 = 7 cm. They are equal.
Answers: 5 cm greater than; no fertilizer; equal.
Check: The two boxes have the same width on the number line (7 units each), which confirms the equal IQRs ✓.
Tip: On the GED, two plots can tie on one measure. Compute each measure instead of judging by eye.
Question 9 of 10 · Dot plots, histograms and box plots
Eleven adults reported how many hours they slept last night:
4, 5, 6, 6, 7, 7, 8, 8, 8, 9, 11
Which box plot correctly represents the data?
Hint
Find the five-number summary yourself first. Then look for the plot that matches all five numbers.
Step-by-step solution
The data are already in order. Minimum = 4, maximum = 11.
Median: 11 values, middle is position 6: 7.
Q_1: median of the lower five values 4, 5, \mathbf{6}, 6, 7 → 6.
Q_3: median of the upper five values 8, 8, \mathbf{8}, 9, 11 → 8.
Five-number summary: 4, 6, 7, 8, 11.
Compare: Plot A has median 8, Plot B has whiskers at 5 and 9, Plot D has median 7.5. Only Plot C shows 4, 6, 7, 8, 11.
The correct plot is Plot C.
Check: In Plot C, the whiskers reach the true smallest and largest values (4 and 11), and the median line sits at 7, with 5 values on each side ✓.
Tip: To match a box plot, check all five numbers. Wrong choices often get four right and one wrong.
Question 10 of 10 · Scatter plots and two-variable data
Fill in
A phone company studied its customers' monthly bills. Let x be the number of gigabytes (GB) of data a customer used and y the monthly bill in dollars. The trend line for the data passes through the points (2, 52) and (6, 84).
The y-intercept of the trend line represents the predicted bill for a customer who uses no data. What is that predicted bill?
$
Type your answer in the box. Fractions like 3/4 are fine.
Hint
First find the cost per GB using the two points. Then work back from one of the points to x = 0.
Step-by-step solution
Find the slope (cost per GB):
m = \frac{84 - 52}{6 - 2} = \frac{32}{4} = 8
Each GB adds about $8 to the bill.
Use y = mx + b with the point (2, 52):
52 = 8(2) + b52 = 16 + bb = 36
The y-intercept is (0, 36): with x = 0 GB, the predicted bill is $36.
The predicted bill with no data is $36.
Check: Use the other point: 8(6) + 36 = 48 + 36 = 84 ✓
Tip: In real-world models, the y-intercept is the starting value, like a base monthly fee, and the slope is the cost per unit. A quick way to work back: from x = 2 to x = 0 is 2 GB fewer, so subtract 2 \times \$8 = \$16 from $52.